Friction cone b is keyed to shaft 1 and rotates about fixed axis A-A. Roller 2 can slide along shaft 3 on feather key d, rotates with this shaft about fixed axis B-B and is in contact at point K with cone b. Angle γ between axes A-A and B-B is equal to one half of the apex angle of cone b. The transmission ratio from shaft 1 to shaft 3 is i₁₃=ω₁/ω₃=n₁/n₃=r/(R-a*sin(γ)) where ω₁, ω₃, n₂ and n₃ are the angular velocities and speeds (in rpm) of shafts 1 and 3, r is the radius of roller 2, a is the variable distance from point K in the central cross section of roller 2 to point D at the large end of cone b, and R is the radius of the large end of the cone.
$3474$CF,IV$